Friend of mine sent me the following puzzle

1+1=3

2+2=4

4+3=5

6x2=6

5-0=4

9/9=3

10-5=4

3x3=4

9+1=3

8/4=3

His clue to solving it: "What is in MATH is in ENGLISH"

Any ideas on the logic behind it?

I have no clue how to start this puzzle without employing any guesswork. Is there a definitive way to solve?

According to the website, all work should deal with whole numbers.

Been staring at this Binario puzzle for the longest time and am so so so stuck. Can anyone help me out, please??

(For those who don’t know Binario, here are the ground rules:

• you can only use 1 and 0
• each column/row needs an equal amount of each number, in this case 7x1’s and 7x0’s
• you cannot have 3 of the same next to each other, neither horizontally nor vertically
• you cannot have duplicate rows/columns)

I’m missing a few

Guys I have looked everywhere for a solution to this and I have no idea what the brand is. It came in a box full of a bunch of other fidgets and I took it apart without looking at how it was put together. If anyone could help me that’d be awesome! Thanks in advance.

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I've been challenging myself to play harder masyu puzzles, and have been having difficulty with larger boards. I feel like I get to a point where I've done all the obvious solutions and have used up all the strategies I know to force solutions out, and then all that's left is guessing and checking solutions. So far the only clever force I've really come up with is noticing that if I only have one space between a straight line or black stone and double white stones(ex: =_ww or b_ww; where = is a line, _ is a blank space, b is a black stone, and w is a white stone), the line can't keep going in the direction and must turn or the black stone must have a line going the opposite direction as the double white stone(=b_ww). Does anyone have any clever forces they could share or helpful tips? It's a daily puzzle so I don't want to break the rule about posting puzzles in ongoing competitions, but I'd appreciate any help in the DMs or comments if allowed.

My boyfriend and I cannot figure this out. It’s not 3577, Clue one: one color = one number Clue two: from smallest to largest

I was helping someone with a sudoku, and they showed me this hint. I understand the connections and implications of the 3/4 in bulbs r2c5 and r8c5, and i think this is shown with the pencils we put in, but i don't follow the logic to say that r1c6 or r4c9 must be an 8.

I was given this puzzle but it's not really my thing but you might like it:

I have 30 red balls, 30 blue balls, and 30 green balls. I also have a red bin, a blue bin, and a green bin. I want to put all the balls into their corresponding bin. However, I'm lazy, so I'm throwing them.

The red bin is nearest. When I throw a red ball, there's an 80% chance it'll land in the red bin. The blue bin is a bit further away. When I throw a blue ball, there's a 60% chance it'll land in the blue bin. The green bin is the furthest away. When I throw a green ball, there's only a 20% chance it'll land in the green bin.

Before every throw, I flip a coin. If it comes up heads, I'll close my eyes before throwing the ball. If it comes up tails, I won't. I do this solely to make things more difficult for you because, frankly, I'm the absolute worst. When my eyes are closed, I only have a 10% chance of getting whichever ball I happen to be holding into its corresponding bin. Curiously, this isn't affected by the fact that some of the bins are further away than others. Why? No idea. Magic, I guess.

If a ball misses, it goes on the floor. It's impossible for me to, say, throw a red ball into the blue bin by mistake. I throw the balls completely at random.

Once I've thrown all 90 balls, how many will be on the floor?

There are 12,000 cards. One side of each card is blank, but written on the other side is a different whole number (randomly generated) between -infinity and +infinity, but excluding those 2 numbers. Ignore the mechanics of writing very large numbers, that doesn't come into play. The cards are randomly placed number side down into a machine that deals one card at a time (like in casinos). A very logical mathematician is brought into the room and is told the number of cards in the machine is 12,000, each has a different number and the range of numbers is between -infinity and +infinity, but excluding both.

The machine deals one card at a time. On getting the card the mathematician looks at it and must declare there and then if the card he has just received has the highest number of all the 12,000 cards (of those already dealt and those yet to be dealt). If he declares the card just dealt to be the one with the highest number, the game ends, otherwise it runs until all cards are dealt. Remember, he can only declare the card just dealt to be the highest. He can't point to a card that was previously dealt and declare that to be the highest and obviously cannot see the cards yet to be dealt.

Before playing, the mathematician spends a few minutes thinking about the problem.

What are the odds of him/her stopping on and declaring the card with the highest number:

a. 1 in 12,000 or worse,

b. 1 in 500 or worse

c. 1 in 100 or worse

d. 1 in 10 or worse

e. 1 in 5 or worse

f. Better than 1 in 5.

And why......

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Found this math puzzle on Facebook. They want you to find the distance between the centers of the circles. No one in the comments knows the answer. Is this solvable?

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https://preview.redd.it/9jribk85emrc1.png?width=420&format=png&auto=webp&s=cc9ce768a49bc98d27ec84345a5d7c8a3234edd2

you are allowed to tamper with them 9 times before they reset

lights turns off or on depending on which ones are adjacent (up right down left)

on light turns off/off light turns on

the goal is to turn all the lights on.

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So if i press one, the row and column of this piece lights up/goes out if its lit

Any recommendations? I prefer logic puzzles more than anything.

Tomorrow's Rain Sun Rain

I was given this Tangram puzzle, but I can't figure out how to arrange the pieces so that it forms the figure shown in the box. Does anyone have any ideas? (I tried to take the photo in a way that you can maybe cut out the pieces and try for yourselves)

6 pieces trangram