/r/funmath
I happen to like arithmetic, but that's not all math is! I didn't when I was a kid, but that's because I sucked and had some uninspiring teachers. I made this place to post some math I think is inspiring, interesting, or cool.
I'm not actively promoting this, but I often x-post from other subreddits, so that's probably what brought you here.
Feel free to subscribe and post stuff you find interesting as well. If you want to be a mod then message me.
I happen to like arithmetic. I didn't when I was a kid, but that's because I sucked and had some uninspiring teachers. I made this place to post some math I think is inspiring, interesting, or cool.
I'm not actively promoting this, but I often x-post from other subreddits, so that's probably what brought you here.
Feel free to subscribe and post stuff you find interesting as well. If you want to be a mod then message me.
Other Resources:
/r/funmath
Was thinking of how to find a birth year that would be equal to someone’s age. Ended up with the following.
(100-x)+y = x
Simplified to:
y + 100 = 2x
Where x = last two digits of birth year and age
And y = last two digits of current year
I tried to post this in psychology but they’re losers and don’t allow text script.
Do you believe if nobody could leave there mark on social media or even other literature or music sport etc. besides country of origin+their initials & birth year, experts would be able to identify who was posting the content bas3d on what was posted?
I’ll help with some basic math
26 characters in alphabet. Initials would have to match up 3 times.+birth year 40m pop Canada. 370k babies are born here a year. No data of new born immigration rate available on general search.
So I can’t remember the formula but I think it’s probably around 200 without putting factors in like “general names” would have the exact same initial + birth year.
Fantasy theoretical fun of the day? :) Take this theory as far as you want maybe say you could track 130 or 20 out of the year and initial :) of course you would need beyond state of the arc military grade nasa gear but w/e let’s say you had it.
Take nearly any number with two or more digits and reverse order those digits to create a mirrored number. If those two numbers are subtracted from each other, the result will always be a multiple of three or nine. Also, the result number's digits will always equal nine when added together (sometimes this step must be repeated once or more until the single digit nine is arrived at). Obviously, any numbers with all like digits are excluded from this as well as those like 141 and 161. A number with any zeros after the first digit like forty would be 40 minus 04 for 36.
A couple of examples,
18, 81 - 18 = 63, 63 ÷ 3 = 21, 63 ÷ 9 = 7, 6 + 3 = 9
1234567, 7654321 - 1234567 = 6419754, 6419754 ÷ 3 = 2139918, 6419754 ÷ 9 = 713306, 6419754 with its digits added together equals 36 which then equals 9
What would you, as someone who likes math, like to receive?
Any cute/inspiring books? Thats pretty much the only math thing I can come up with.
Two isolated lines (which are price points basically, one unit of time apart, each).
Line 1:
Line 2:
What is the "Angle" in degrees between both lines? To me this is a simple X/Y Graph where for both 'Price Point 1' is X = 0, and Price Point 2 is X = 1.
arctan(1.2-1.1) - arctan(0.7-1.3) = DISASTER.
Cuuld someone Please provide answer to above in bolded text?
This is not home work I am a grown man who can't math and am facing existential dread what seems basic. Thanks.
This question was posed to me by u/Xane256 in a comment to a post I made about rolling parabolas.
I haven't yet worked out the precise height. Still trying to figure out how. But I know it's just a little bit less than 5.4
Oh and please don't hate on me for my poor Blender skills. Literally just started using it today.
https://i.imgur.com/QhaAknM.png
https://www.geogebra.org/calculator/xtw3c4mh
I've been on a parabola kick lately. Made this cool applet to show where a parabola would come to a stable resting point as a function of its height. Forgive my inefficient construction of this applet, i'm not a geogebra wiz. If anyone has a way to optimize this kind of thing please let me know i'm trying to get better.
Some fun exercises...
*Easy... Where along the parabola's central axis is the center of mass as a function of its height? (use f(x) = x^2)
**Medium... What's the tallest the parabola can be before the vertex is no longer stable?
***Hard... How tall must the parabola be if you want the flat part of the parabola to rest at a 45 degree angle?
****Extra Hard.... How tall should the parabola be so that the point of contact on the rolling surface is 1 unit from the origin (1,0) (assume non-slip "surface")?
I have created a video that looks at the math behind the game Animal Crossing for Nintendo Switch! My using proportional relationships, we can find out how much each item is worth in materials, and use that to find a way to make MORE BELLS FASTER! Check it out! :)
Guys, I have really important question. Suppose I have (n) wet wipes, they are all similar (a*b), with equal thickness (t). How should I fold them to get biggest area with predefined lower limit for thickness? What is the optimal way to fold to get it with minimum number of folds? Is there any known algorithm for this kind of problems?
Thanks)
I'm at a point in my life where I'm applying for jobs where they make you pass a basic logic and reasoning test before proceeding to an interview. So, grade 12 math is far behind and I haven't been practicing basic arithmetic for the past 10 years, and I feel like I could polish those skills a bit.
Do you guys have recommendations for applications that would give me fun math/arithmetic/logic problems to solve?
Hi everyone! r/Hexaflexagons is a place to discuss the amazing thing known as Hexaflexagons. It is a math concept/thing that is super fun to make. However, instead of googling, seriously look on our subreddit. If I see more basic Help Requests I will pin the basic instructions. Please do check out this place.
To infiltrate and seize the city of Troy, Ulisses decided to hide twenty hoplite warriors inside a giant wooden horse.
Three were lean Spartans.
Nine were stocky and thirteen were Athenians.
How many were stocky Spartans?
How many were lean Athenians?