I asked lots of people from Reddit about how much they could solve from imo Olympiad without time limit vs in time limit of Olympiad 9h. 16 people answered on that. Means that they tried both variants timed and untimed. Before understanding results you should know that level of difficulty is different from different years of imo. 4 items from 2017 is as difficult as all 6 items from 2005 year. You can see that in statistics on website. Average speed on timed usually looked like 2.5 if someone can solve 2-3 on timed case. 15 of those 16 could solve at least 2 items in complex year. Or 3 in simple year.

I found that more someone can solve untimed so more will be distance from his untimed score to his timed score. For example someone can do 3 timed and 4 untimed. Other can do 4 timed and 6 untimed. So that 6-4 > 4-3.

I was asking about actual results. So that means how much someone actually solved not how much he predicts that he can solve.

Untimed means without time limit.

So here are norms. Av s = means average speed. S u = means how much someone can solve in simple year as 2005. Untimed. C u = means how much someone can solve in complex year as 2017. Untimed.

Av s 2.4 => s u 3.3. , c u 2.2

Av s 3.625 => s u 6. , c u 4

Av s 4.625. => s u 6 , c u 5.5

Which means that if someone solved all 6 items in 2005 or 4 items in 2017 I predict his average speed on timed Olympiad as 3.625

Hello,

In my job we have a list to clear names of clients between 2 co-workers. We like to assort them based on alphabetical order of last names and to make us do them evenly, we have been doing one worker doing names A-M and the other N-Z. However, of course this is not truly equal, the worker who is doing A-M has a lot more work due to more people having last names in that range. Based on statistics of average first letters of last names, what would be the most optimal split for the two coworkers?

0.999... + 0.111...

= (0.9 + 0.09 + 0.009 + ...) + (0.1 + 0.01 + 0.001 + ...)

= 0.9 + 0.1 + 0.09 + 0.01 + 0.009 + 0.001 + ...

= (0.9 + 0.1) + (0.09 + 0.01) + (0.009 + 0.001) + ...

= 1 + 0.1 + 0.01+ 0.001 + ...

= 1.111...

= 1 + 1/9,

therefore 0.999... + 1/9 = 1 + 1/9. Subtract 1/9 from both sides, then 0.999... = 1.

Point C is on line segment AB, where AB = 6 and AC = 4.
An equilateral triangle CEG is formed with C as one of its vertices.
Lines AE and BG are drawn.
When the sum of AE + BG is minimized, find the area of triangle CEG.

For instance, 443 = 44+43=87

822 = 82+22=104=4

099 = 9+99=108=8

130+13+30=43

If that makes any sense

So far, I have gotten these numbers: 4 7 8 9 13 14 16 19 21 24 43 45 49 51 68 71 80 84 87 87 89 96 96

I am not a student, just curious.

Dear Members and Moderators.

Please ignore if this is not the right way to get started here.

I want to share https://visualtrigonometry.com/ with the group here. A VISUAL WAY to calculate sin, cos, tan, etc. (Trigonometric Calculators) and arcsin, arccos, arctan, etc. (Inverse Trigonometric Calculators) for the community's use; especially students.

Any critical feedback is welcome!

Regards,
Swapneel Shah

CompetifyHub is happy to announce the next level in the Competify family: CompetifyPlus (https://competifyplus.com/)

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We are now available on Google Play Store.
You can find zero to hero math exercises including Arithmetic to Calculus and Linear algebra

You can download on
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Enjoy

Hey everyone! We're hosting a Thanksgiving Arithmetic Dash over the next nine days. This is a three-minute speed-based math contest consisting of simple arithmetic questions - and we will be awarding certificates to the top 10% of participants in each country, state (if US), and age group.

We hope it is fun, and a cool way to compete against others from your country, state, or age!

The contest is here: https://mathdash.com/contest/thanksgiving-arithmetic

We also recommend that you participate in the practice contest beforehand in order to get a feel for the format - the practice contest is here: https://mathdash.com/contest/thanksgiving-arithmetic-practice

Good luck!

I've always thought that practicing mental math could be more engaging, so I decided to build a simple game that combines the fun of classic Tetris with quick math challenges. In the game, numbers fall from the top, and you have to solve the math problems before they hit the bottom.

It's designed to help improve fast counting and mental calculation skills in a fun way. If you're interested in giving it a try, here are the links: Android and iOS

I’d love to hear your thoughts and any feedback you might have!

https://preview.redd.it/sroj8jk1ak1e1.png?width=1506&format=png&auto=webp&s=12d487ae594586f14df5971138fcbf52e3a90bee

Find surface area

Hey everyone! I made a game called equ8 (“equate”). You’re given four numbers, standard operators, and a target number, and the goal is to create as many equations as possible to equal the target number. For each correct equation, you get points and level up. You can share your score and compete with your friends.

Check it out at https://playequ8.com

Let me know what you think!